Question 377650
Square both sides.
{{{(x+4)^2=16(x+1)}}}
{{{x^2+8x+16=16x+16}}}
{{{x^2-8x=0}}}
{{{x(x-8)=0}}}
Two solutions:
{{{highlight(x=0)}}}
.
.
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{{{x-8=0}}}
{{{highlight(x=8)}}}