Question 377631
Use the common denominator, {{{x^2-16=(x-4)(x+4)}}}
{{{1/(x-4) - 1/(x+4)= (x+4)/((x+4)(x-4))- (x-4)/((x+4)(x-4))}}}
{{{1/(x-4) - 1/(x+4)= (x+4-(x-4))/((x+4)(x-4))}}}
{{{1/(x-4) - 1/(x+4)= (x+4-x+4)/((x+4)(x-4))}}}
{{{1/(x-4) - 1/(x+4)= highlight((8)/((x+4)(x-4)))}}}