Question 377513
suppose that y varies directly as the sqaure root of x, and that y=32 when x=16. What is y when x=50?
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{{{ y (alpha)  sqrt(x)}}}
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{{{y = k*sqrt(x)}}}
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x=16,y=32
plug the value 
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{{{32=k*sqrt(16)}}}
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32=4k
/4
k=32/4
k=8
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{{{y = k*sqrt(x)}}}
x=50, k= 8
{{{y=8*sqrt(50)}}}

y =56.56
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