Question 377365
{{{(4-3i)/(3-2i)=((4-3i)/(3-2i))*((3+2i)/(3+2i))}}}
{{{(4-3i)/(3-2i)=(12+8i-9i-6i^2)/(9+6i-6i-4i^2)}}}
{{{(4-3i)/(3-2i)=(18-i)/(9+4)}}}
{{{(4-3i)/(3-2i)=(18-i)/(13)}}}
{{{highlight((4-3i)/(3-2i)=(18/13)-(1/13)i)}}}