Question 377456
1. 210.0/365  = 0.5453, to 4 decimal places.

2. Here {{{mu = 0.5453}}}, and we use the Poisson distribution.  Then {{{P(L > 1) = P(L >= 2) = 1 - e^(-.5453)(0.5453^0/0!) - e^(-.5453)(0.5453^1/1!) = 0.1042}}}.

3.  Based on the chances we obtained in 2., 1 out of 10 babies is born with low weight.