Question 377446
One Leg Of A Right Triangle Is 21 Inches Longer Than The Smaller Leg, And The Hypotenuse Is 24 Inches Longer Than The Smaller Leg. Find The Lengths Of The Sides Of The Triangle.
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smaller leg = x
longre leg = x+21
hypotenuse = x+24
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Hyp^2 = leg1^2 + leg2^2
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(x+24)^2=(x+21)^2+x^2
x^2+48x+576=x^2+42x+441+x^2
re write the equation 
x^2+x^2-x^2-48x+42x-576+441=0
x^2-6x-135=0
x^2-15x+9x-135=0
x(x-15)+9(x-15)=0
(x-15)(x+9)=0
x= 15 ignore -9
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The sides are 15, 36,39 inches
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