Question 376829
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Hi,
*Note: {{{z = blue(x - mu)/blue(sigma)}}}
     z = 600-450 /100 = .5     NORMSDIST(0.5)  = .691462
     z = 400-450 /100 = -.5    NORMSDIST(-0.5) = .30854
P( -.5 < z <.5) = .691462 - .30854 = .3829  Or 38.29%
Receiving score of 630:
     z = 630-450 /100 = 1.8    NORMSDIST(1.8)  = .9641
96.41% score less and 3.59 % score better

upper 25%
z = NORMSINV(0.75)= .6745
    .6745 *100  + 450 = 517 Would need score >517 to be considered for admissions