Question 376612
{{{2x=sqrt(2x+3)/ 2}}}
{{{4x^2=(2x+3)/4}}}
{{{16x^2-2x-3=0}}}
{{{(8x+3)(2x-1)=0}}}
Two solutions:
{{{8x+3=0}}}
{{{8x=-3}}}
{{{highlight(x=-3/8)}}}
.
.
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{{{2x-1=0}}}
{{{2x=1}}}
{{{highlight(x=1/2)}}}