Question 376616
{{{1-1/x-12/x^2=0}}}
{{{x^2-x-12=0}}}
{{{(x-4)(x+3)=0}}}
Two solutions:
{{{x-4=0}}}
{{{highlight(x=4)}}}
.
.
.
{{{x+3=0}}}
{{{highlight(x=-3)}}}