Question 376714
{{{2.5 = sqrt((1.5-0)^2 + (2 - y)^2) = sqrt(2.25 + 4 - 4y + y^2) = sqrt(6.25 - 4y + y^2)}}}.  Then 
{{{6.25 = 6.25 - 4y  +y^2}}},
{{{0 = -4y + y^2}}}, or
0 = y(-4 + y), or y = 0, 4.  There are two possibilities: the point (0,0) or the point (0, 4).