Question 376663
h(t)=-4.9t^2+19.6t
h= 0 when it touches the ground
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-4.9t^2+19.6t=0
-4.9t^2=-19.6t
/-4.9t
t=-19.6t/-4.9t
t=4 seconds.
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As you will see from the graph the height is = 0 at t=4 seconds
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{{{graph(300,300,-1,5,-5,22,(-4.9x^2+19.6x))}}}
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m.ananth@hotmail.ca