Question 376611
*[Tex \LARGE \log(x)-\log(7)-\log(8)] ... Start with the given expression.



*[Tex \LARGE \log(x)-(\log(7)+\log(8))] ... Factor out a negative from the last two terms.



*[Tex \LARGE \log(x)-\log(7\times8)] ... Combine the last two logs using the identity {{{log(b,(A))+log(b,(B))=log(b,(A*B))}}}



*[Tex \LARGE \log(x)-\log(56)] ... Multiply



*[Tex \LARGE \log(\frac{x}{56})] ... Combine the two logs using the identity {{{log(b,(A))-log(b,(B))=log(b,(A/B))}}}



So *[Tex \LARGE \log(x)-\log(7)-\log(8)=\log(\frac{x}{56})]



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