Question 376535
solve {{{(3+4i)/(5-i)}}}
Multiply be the conjugate of the denominator over itself
{{{(3+4i)/(5-i)}}}*{{{(5+i)/(5+i)}}} = {{{(15 + 3i + 20i + 4i^2)/(25 - i^2)}}} = {{{(15 + 23i +  4(-1))/(25 - (-1))}}} = {{{(15 + 23i -4)/(25 + 1)}}} = {{{(11 + 23i)/26}}}