Question 376185
{{{((x^2+4x+3)/(x^2-3x+2))*((x-1)/(3x+3))=(( (x+3)(x+1) )/((x-2)(x-1)))*((x-1)/(3(x+1)))}}}
{{{((x^2+4x+3)/(x^2-3x+2))*((x-1)/(3x+3))=highlight( (x+3) /(3(x-2)))}}}