<PRE><B>Question 375866</B>
  &lt;pre&gt;&lt;font size = 3 color = &quot;indigo&quot;&gt;&lt;b&gt;
Hi
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]
log2x-log(x-7)=log3 
log2x-log(x-7)-log3=0
log(2x/3(x-7) = 0 
*[tex \LARGE \ \ \ \ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
10 ^0 = 2x/3(x-7)
1 = 2x/3(x-7)
3(x-7)= 2x
3x - 21 = 2x
x = 21</PRE>