Question 376158
{{{sqrt( 32  - 4x ) = x}}}

square both sides. Note that squaring means that you can get solutions that are not suitable, in this case if you get a solution of a negative x:

{{{32-4x = x^2 }}}
*[invoke explain_simplification "32-4x = x^2" ]

x = -8 is a WRONG root, because square root cannot be negative. So your answer is x=4.