Question 375863
Write an equation of the line containing the given point and parallel to the given line.
 Express in y = mx+b.
(-6,2;) 6x = 5y+4
:
Find the slope of the given equation, put it in the slope intercept form y = mx+b:
6x = 5y + 4
-5y = -6x + 4
y has to be positive, multiply by -1
5y = 6x - 4
divide by 5
y = {{{6/5}}}x - {{{4/5}}}
:
The slope = {{{6/5}}}, a parallel line will have the same slope
Use the point/slope form y - y1 - m(x - x1)
:
y - 2 = {{{6/5}}}(x - (-6))
y - 2 = {{{6/5}}}(x + 6)
y - 2 = {{{6/5}}}x + {{{36/5}}}
y = {{{6/5}}}x + {{{36/5}}} + 2
y = {{{6/5}}}x + {{{36/5}}} + {{{10/5}}}
y = {{{6/5}}}x + {{{46/5}}}; is the parallel line