Question 376110
log(2)((3x-2)/(x-5)) = 4,
OR {{{2^4 = (3x-2)/(x-5)}}},
{{{16(x-5) = 3x - 2}}},
16x - 80 = 3x - 2,
13x = 78,
x = 6.  this value satisfies the original equation, and so is the final answer.