Question 376021
Once pet's age was 2 times Paul’s age. But at that time pet's  age= Paul’s current age . Sum of their present ages is 40. How old is pet now? 

Let x = the age of pet now
    y = the age of Paul now

 x-y = number of years ago when pet's age equals Paul's current age

x - (x-y) = 2[y-(x-y)]
       y  = 2(2y-x)
       y  = 4y - 2x
      2x  = 3y
       x  = 1.5y
 
1.5y+y = 40
     y = 16
     x = 24

Pet is 24 years old now.