Question 376010
The perimeter of a standard high school basketball court is 268 ft. The length is 34 ft greater than the width. Find the length and the width of the court.
.
Let w = width
then
w+34 = length
.
2(w + w+34) = 268
dividing both sides by 2:
(w + w+34) = 134
2w+34 = 134
2w = 100
w = 100 ft. (width
.
Length:
w+34 = 100+34 = 134 ft