Question 375992
How many L of a 10% saline solution must be added to 40 L of a 20% saline solution to obtain a 14% saline solution?
.
Let x = amount (L) of 10% saline solution
then

.10x + .20(40) = .14(x+40)

.10x + 8 = .14x + 5.6

8 = .04x + 5.6

2.4 = .04x

60 liters = x