Question 41401
 
  {{{(2x^2-x-3)/(3x^2+7x+4)*(3x^2-11x-20)/(4x^2-9)}}}
 First of all we should factorise all the expressions. i.e.
 = {{{highlight(2x^2-x-3)/highlight(3x^2+7x+4)*highlight(3x^2-11x-20)/highlight(4x^2-9)}}}
 = {{{((2x-3)(x+1)(3x+4)(x-5)/((3x+4)(x+1)(2x+3)(2x-3)))}}}
 After cancelling similar factors,
 ={{{(cross(2x-3)cross(x+1)cross(3x+4)(x-5)/(cross(3x+4)cross(x+1)(2x+3)cross(2x-3)))}}}
 = {{{(x-5)/(2x+3)}}}.  Answer.  I guess you have understood this. 

gsm