Question 375915
{{{((-23x^4y^0)/(92x^-2y^-3))^(-3)=((-x^4y^0)/(4x^-2y^-3))^(-3)=((-x^(4-(-2))y^(0-(-3)))/4)^(-3)=((-x^6y^3)/4)^(-3)=((-x^6y^3)^(-3))/(4^(-3))=((-x^6)^(-3)(y^3)^(-3))/(4^(-3))=(-x^(-18)y^(-9))/(1/64)=-64/(x^18y^9)}}}



So {{{((-23x^4y^0)/(92x^-2y^-3))^(-3)=-64/(x^18y^9)}}}



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