Question 375702
{{{(b^(1/2)*b^(-7/8))/ b^(1/8)=b^(4/8-7/8-1/8)}}}
{{{(b^(1/2)*b^(-7/8))/ b^(1/8)=b^(-4/8)}}}
{{{(b^(1/2)*b^(-7/8))/ b^(1/8)=b^(-1/2)}}}
{{{(b^(1/2)*b^(-7/8))/ b^(1/8)=highlight(1/sqrt(b))}}}