Question 375783
  <pre><font size = 3 color = "indigo"><b>
Hi
Finding the x-intercepts for the graph of the equation 
y=x^2-3x-4 (y=0 when the graph crosses the x-axis)
0 = x^2-3x-4
solving by factoring
(x-4)(x+1)=0 Note:SUM of the inner product(-4x) and the outer product(1*x) = -3x
(x-4)=0
x=4
(x+1)=0
x = -1 
{{{drawing(300,300, -6, 6, -6, 6,grid(1),
circle(-1, 0,0.2),
circle(4, 0,0.2),
graph( 300, 300, -6, 6, -6, 6, x^2-3x-4
))}}}