Question 375664
{{{y = (x^2 - 1)/(x+1)}}}.  The domain of this function is the set of all real numbers except x = -1.  That said, the expression is reduced as follows:
{{{y = (x^2 - 1)/(x+1) = ((x-1)(x+1))/(x+1) = x-1}}}, with x not equal to -1.
The x-intercept:  x-1 = 0, or x = 1.
The y-intercept:  y = 0-1 = -1.
There are NO slant, vertical, or horizontal asymptotes.