Question 375529
{{{3(1+d)-5=3d-2}}} Start with the given equation.



{{{3+3d-5=3d-2}}} Distribute.



{{{3d-2=3d-2}}} Combine like terms on the left side.



{{{3d=3d-2+2}}} Add {{{2}}} to both sides.



{{{3d-3d=-2+2}}} Subtract {{{3d}}} from both sides.



{{{0d=-2+2}}} Combine like terms on the left side.



{{{0d=0}}} Combine like terms on the right side.



{{{0=0}}} Simplify.



Since this equation is <font size=4><b>ALWAYS</b></font> true for any d value, this means d can equal any number. 


So there are an infinite number of solutions.



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Jim