Question 375417
Factor the following polynomial.

{{{18x^2y-24x^2-27y+36}}}

<pre>
First factor out the common factor 3, using a bracket, so that
parentheses may be placed within:

{{{"3["}}}{{{6x^2y-4x^2}}}{{{-9y+12}}}{{{"]"}}}


I'll do some coloring for clarity:

{{{"3["}}}{{{red(6x^2y-4x^2)}}}{{{green(-9y+12)}}}{{{"]"}}}

Factor {{{red(2x^2*"")}}} out of the two red terms and
factor {{{green(-3*"")}}} out of the two green terms

{{{"3["}}}{{{red(2x^2*(3y-4))}}}{{{green(-3(3y-4))}}}{{{"]"}}}

Now I will recolor the expressions

{{{"3["}}}{{{green(2x^2)*red((3y-4))}}}{{{green(-3)red((3y-4))}}}{{{"]"}}}

Factor out the common red factor, and put the two green factors 
as a sum in parentheses:

{{{"3["}}}{{{red((3y-4))}}}{{{green((2x^2-3))}}}{{{"]"}}}

The brackets are no longer needed and neither is the special coloring,
so the final answer is:

{{{3(3y-4)(2x^2-3)}}}

Edwin</pre>