Question 375307
h(t)= 104t-16t^2
max height is at the vertex.
.
Vertex is when:
t = -b/(2a) = -104/(2*(-16)) = -104/(-32) = 3.25
.
h(3.25)= 104(3.25)-16(3.25)^2
h(3.25)= 338-169
h(3.25)= 169 feet