Question 375357
Plug each point in the equation.
I'll do the first, you do the rest.
{{{(x-3)^2+(y+4)^2=25}}}
{{{(6-3)^2+(0+4)^2=25}}}
{{{3^2+4^2=25}}}
{{{9+16=25}}}
{{{25=25}}}
True, so ({{{6}}},{{{0}}}) is on the circle.
Now you also know D) is not the solution.
Now check the remaining two points.