Question 375360
Use the common denominator, {{{(x-1)^2}}}
{{{(x + 1)/(x-1) - 1/(x-1)^2=((x+1)(x-1))/(x-1)^2-1/(x-1)^2}}}
{{{(x + 1)/(x-1) - 1/(x-1)^2=((x+1)(x-1)-1)/(x-1)^2}}}
{{{(x + 1)/(x-1) - 1/(x-1)^2=(x^2-1-1)/(x-1)^2}}}
{{{highlight((x + 1)/(x-1) - 1/(x-1)^2=(x^2-2)/(x-1)^2)}}}