Question 41332
{{{y = 4x^2 - 8x + 1}}}
{{{y/4 = x^2 - 2x + 1/4}}}
{{{y/4 - 1/4 = x^2 - 2x}}}
{{{y/4 - 1/4 + 1 = (x - 1)^2}}}
{{{y/4 + 3/4 = (x - 1)^2}}}
{{{y/4 = (x - 1)^2 - 3/4}}}
{{{y = 4(x - 1)^2 - 3}}}