Question 375264
{{{(-i)/(8 + 8i)=((-i)/(8 + 8i))*((8-8i)/(8-8i))}}}
{{{(-i)/(8 + 8i)=(-8i+8i^2)/(64-64i+64i-64i^2)}}}
{{{(-i)/(8 + 8i)=(-8i-8)/(64+64)}}}
{{{(-i)/(8 + 8i)=(-8(1+i))/(8(16))}}}
{{{(-i)/(8 + 8i)=-(1+i)/16}}}
{{{highlight((-i)/(8 + 8i)=-(1/16)-(1/16)i)}}}