Question 375186
{{{F=P(1+i)^t}}}
{{{2000=1000(1+0.045)^t}}}
{{{2=(1.045)^t}}}
{{{t=log(1.045,(2))}}}
{{{highlight(t=log((2))/log((1.045)))}}}
or approximately,
{{{t=15.75}}} years