Question 375017
8+8/3+8/9+8/27...=8(1+1/3+1/9+1/27+...)=8+8(1/3+1/9+1/27+...)
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{{{S=8+8*sum((1/3)^i,i=1,infinity)}}}
{{{S=8+8*((1/3)/(1-1/3))}}}
{{{S=8+8((1/3)/(2/3))}}}
{{{S=8+8*(1/2)}}}
{{{highlight(S=12)}}}