Question 375020
1.{{{x^2+y^2=100}}}
2.{{{3x-y=10}}}
Use substitution,
From eq. 2,
{{{y=3x-10}}}
{{{y^2=9x^2-60x+100}}}
Substitute into eq. 1,
{{{x^2+9x^2-60x+100=100}}}
{{{10x^2-60x=0}}}
{{{10x(x-6)=0}}}
Two solutions:
{{{10x=0}}}
{{{highlight(x=0)}}}
Then
{{{y=3(0)-10}}}
{{{highlight(y=-10)}}}
.
.
.
{{{x-6=0}}}
{{{highlight_green(x=6)}}}
Then 
{{{y=3(6)-10}}}
{{{y=18-10}}}
{{{highlight_green(y=8)}}}
.
.
.
{{{drawing(300,300,-12,12,-12,12,grid(1),circle(0,-10,0.5),circle(6,8,0.5),graph(300,300,-12,12,-12,12,0,sqrt(100-x^2),3x-10),graph(300,300,-12,12,-12,12,0,-sqrt(100-x^2)))}}}