Question 374988
Do you mean {{{a(n)=(-2)^n+2/n^2}}}??
If so, I'll do two, you finish.
{{{a(1)=(-2)^1+2/1^2=(-2)+2/1=-2+2=0}}}
{{{a(2)=(-2)^2+2/2^2=4+2/4=4+1/2=9/2}}}
Continue in the same manner.