Question 374907
{{{ log(2,x)+log(2,x-6) =4 }}}
{{{ log(2,x(x-6)) =4 }}}
{{{ x(x-6) = 2^4 }}}
{{{ x^2-6x = 16 }}}
{{{ x^2-6x-16 = 0 }}}
{{{ (x-8)(x+2) = 0 }}}
x = {-2, 8}
.
But, x=-2 turns out to be an "extraneous" solution so throw it out leaving:
x = 8