Question 5256
9x - 15y = 120
3x - 5y = 40
y=(40-3x)/-5
<P>
Substituting this value of y in eqn1,we have eliminated variable y from the first equation
<br>
11x - 5y = 80
11x - 5(40-3x)/-5 = 80
multiplying through out by '-5'
-55x - 5(40-3x) = -400
dividing throughout by '-5'
11x +(40-3x) = 80
11x-3x=80-40
8x=40
x=5
<P>
y=(40-3x)/-5
=(40-15)/-5
=25/-5
=-5
<P>
x=5,y=-5
<br>Hope this helps,good luck.