Question 374875
(leg A)^2 + (leg B)^2 = (hypotenuse)^2


The above is called the Pythagorean Theorem.


The hypotenuse is sqrt[29].


leg A = x


leg B = 2x - 8


Just plug that information into the formula above and do the math.


(x)^2 + (2x - 8)^2 = (sqrt[29])^2


Can you take it from here?


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