<PRE><B>Question 374746</B>
the area of a rectangle = L x W
L = 5W
area = w x 5w
area = {{{5w^2}}}
125 = {{{5w^2}}}
{{{sqrt(125)}}} = {{{sqrt(5w^2)}}}
{{{sqrt(25*5)}}} = 5w
{{{5*sqrt(5)}}} = 5w
{{{[5*sqrt(5) / 5}}} = 5L / 5
{{{sqrt(5)}}} = w

L/5 = w
L = {{{5*sqrt(5)}}}

perimeter = 2W + 2L
p = {{{2*sqrt(5)}}} + 2*5*sqrt(5)}}}
p = {{{2*sqrt(5)}}} + 10*sqrt(5)}}}
p = {{{12*sqrt(5)}}}

This was my best guess. Sorry if its wrong.</PRE>