Question 374719
{{{2/log((5^x))=1/16}}}
{{{log((5^x))=2/(1/16)}}}
{{{log((5^x))=32}}}
{{{5^x=10^32}}}
{{{log(10,(5^x))=log(10,(10^32))}}}
{{{x*log(10,(5))=32}}}
{{{highlight(x=32/log(10,(5)))}}}
or approximately,
{{{x=45.782}}}