Question 41177
3x+5y=7
6x-y=-8

Let's multiply the second equation by 5 to create opposite coefficients for y.

3x+5y=7
30x-5y=-40

Now, let''s add the two equations to drop out y.

33x=-33y  (divide each side by 33)
33x/33=-33/33
x=-1

Let's plug the value of x in the first equation (you may plug it in the second equation as well);

3.(-1)+5y=7
-3+5y=7  (move -3 to the right of the equation)
5y=7+3
5y=10     (divide each side by 5)
5y/5=10/5
y=2