Question 374674


{{{x-y=-8}}} Start with the given equation.



{{{-y=-8-x}}} Subtract {{{x}}} from both sides.



{{{-y=-x-8}}} Rearrange the terms.



{{{y=(-x-8)/(-1)}}} Divide both sides by {{{-1}}} to isolate y.



{{{y=((-1)/(-1))x+(-8)/(-1)}}} Break up the fraction.



{{{y=x+8}}} Reduce.



So the equation {{{y=x+8}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=1}}} and the y-intercept is {{{b=8}}} note: the y-intercept is the point *[Tex \LARGE \left(0,8\right)]



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