Question 374576
let the integers be x  x+4
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x+sqrt(x+4)=86
sqrt(x+4)=86-x
square both sides
x+4=(86-x)^2
x+4 = 7396-172x+x^2
x^2-172x-x+7396-4=0
x^2-173x+7392=0
x^2-96x-77x+7392=0
x(x-96)-77(x-96)=0
(x-96)(x-77)=0
x= 96 OR 77
numbers are 77 & 81
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m.ananth@hotmail.ca