Question 374197
{{{2w^2+12w+17=(w+5)^2}}}
{{{2w^2+12w+17=w^2+10w+25}}}
{{{w^2+2w-8=0}}}
{{{(w+4)(w-2)=0}}}
Two solutions:
{{{w+4=0}}}
{{{highlight(w=-4)}}}
.
.
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{{{w-2=0}}}
{{{highlight(w=2)}}}