Question 5170
|x/2 - 2| + 1 < 3
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|x/2 - 2| < 2
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|x/2 - 2| could be positive or negative,
but from the ineqn we understand that it must less than 2.
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hence,if positive,it should greater zero,but less than 2.
ie. 0 < x < 2
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|x/2 - 2| could be negative,ie.
x/2 - 2 < 0
x/2 < 2
x < 4
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our solution would be,
x=]0  2[ U ]+infinity  4[
('U' stands for union)
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hence x=]0  2[
<P>
You dint mention which set it should fall in,Whole or Real or something else.
Either way,its solution seems to be
x=]0  2[