Question 374189
Complete the square in x and y to find the equation of the circle.
{{{x^2+y^2-6x+8=0}}}
{{{x^2-6x+y^2+8=0}}}
{{{(x^2-6x+9)+(y-0)^2+8=9}}}
{{{(x-3)^2+(y-0)^2=1}}}
The circle has a radius of {{{R=1}}}
{{{C=2*pi*R=2*pi*1=highlight(2*pi)}}}