Question 374091
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Let *[tex \Large x] represent the measure of a side of the square.  Then *[tex \Large x\ +\ 2] represents the width of the rectangle and *[tex \Large (x\ +\ 2)\ +\ 2\ =\ x\ +\ 4] represents the length of the rectangle.  The area of the rectangle is therefore *[tex \Large (x\ +\ 2)(x\ +\ 4)\ =\ x^2\ +\ 6x\ +\ 8] which, added to the area of the square, *[tex \Large x^2], equals 64.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x^2\ +\ 6x\ +\ 8\ =\ 64]


Simplify, put in standard form, factor, and solve for *[tex \Large x].


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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