Question 373963
First calculate the sum,
{{{S=(a^3-4a+3)+ (3a-6a^3+2)}}}
{{{S=(a^3-6a^3)+(-4a+3a)+(3+2)}}}
{{{S= -5a^3-a+5}}}
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{{{(-5a^3-a+5)-(4a^3+6a^2-5) =-5a^3-a+5-(4a^3+6a^2-5)}}}
{{{(-5a^3-a+5)-(4a^3+6a^2-5) =(-5a^3-a^3)+(-6a^2)+(-a)+(5-(-5)))}}}
{{{(-5a^3-a+5)-(4a^3+6a^2-5) =highlight(-5a^3-6a^2-a+10)}}}